This is a classroom blog hub for Grade 8 students at Sargent Park School.
Thursday, September 25, 2008
Problem Solving
Here is a problem from a great mathematician. Can you solve it? How many different ways are there to get the answer? Lets find out. Consider this question KRYPTO on steroids.
YAY :) the hardest one to do was 6 i think .. but i got it anyways. eg. (4+4) / +4 The easiest one was probably 0 because all you had to do was make a number, then subtract the same thing .. eg. (-44)+44 .. UUHHMM .. all the other digits were eaasy
12 comments:
i liked this problem harbeck
8-41
YAY :) the hardest one to do was 6 i think .. but i got it anyways.
eg. (4+4) / +4
The easiest one was probably 0 because all you had to do was make a number, then subtract the same thing ..
eg. (-44)+44 ..
UUHHMM ..
all the other digits were eaasy
873
i almost got everything but 6 it's so hard but i got the other ones. i will show #9
4+4+(4/4)=9
Yay :P the easiest one to do is 7. I figured it out so fast.
Here is an example
eg. [44/4]-4=7
i like this problem
lool , me too (:
8-41
i liked this problem too
i think the hardest one was to do 2 because i didnt use brackets for all of them except this one -_- i got (4/4)+(4/4)=2.
(4+4)(4-4)=0
(4-4)+(4/4)=1
((4+4)+4)/4=3
4+4+4/4=5
((4+4)/4)+4=6
(4-4)+(4+4)=8
am i correct
-xtian
I got a lot of them, but when I was looking for two, I just kept getting 8 xD
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