This is a classroom blog hub for Grade 8 students at Sargent Park School.

Thursday, September 25, 2008

Problem Solving

Here is a problem from a great mathematician. Can you solve it? How many different ways are there to get the answer? Lets find out. Consider this question KRYPTO on steroids.

YAY :) the hardest one to do was 6 i think .. but i got it anyways. eg. (4+4) / +4 The easiest one was probably 0 because all you had to do was make a number, then subtract the same thing .. eg. (-44)+44 .. UUHHMM .. all the other digits were eaasy

## 12 comments:

i liked this problem harbeck

8-41

YAY :) the hardest one to do was 6 i think .. but i got it anyways.

eg. (4+4) / +4

The easiest one was probably 0 because all you had to do was make a number, then subtract the same thing ..

eg. (-44)+44 ..

UUHHMM ..

all the other digits were eaasy

873

i almost got everything but 6 it's so hard but i got the other ones. i will show #9

4+4+(4/4)=9

Yay :P the easiest one to do is 7. I figured it out so fast.

Here is an example

eg. [44/4]-4=7

i like this problem

lool , me too (:

8-41

i liked this problem too

i think the hardest one was to do 2 because i didnt use brackets for all of them except this one -_- i got (4/4)+(4/4)=2.

(4+4)(4-4)=0

(4-4)+(4/4)=1

((4+4)+4)/4=3

4+4+4/4=5

((4+4)/4)+4=6

(4-4)+(4+4)=8

am i correct

-xtian

I got a lot of them, but when I was looking for two, I just kept getting 8 xD

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