What I did was I square routed the red box which gave me 3 for the perimeter so the side length of the triangle in the middle is 3 and then I multiplyed the perimeter give from the blue box by 4 which gave me 16 squared centimeters for the blue box, then to find out the hypotenus I added the 3cm from the red box and the 4cm from the blue box which equaled the 7cm of the hypotenus. . So box C is 49 squared cm. FORMULA- 3cm+4cm=7cm 7x7= 49

What I did was I square routed the given area from the red box which gave me 3cm for the perimeter, which makes the side length of the triangle 3cm, after i took the given 4cm from the blue box and added the 3cm from the red box + 4cm from the blue box together which equaled 7cm and thats the hypotenuse. Afterwards i multiplied the side lengths of the "C/big box" together and gave me the area of 49 squared cm. -Rheanna A. 8-17

## 4 comments:

so u just use the red and blue squares to see if it's posible to make the big square which is the hypothenues

-Rosheena Salvador 8-14

yes that is what you do

What I did was I square routed the red box which gave me 3 for the perimeter so the side length of the triangle in the middle is 3 and then I multiplyed the perimeter give from the blue box by 4 which gave me 16 squared centimeters for the blue box, then to find out the hypotenus I added the 3cm from the red box and the 4cm from the blue box which equaled the 7cm of the hypotenus. . So box C is 49 squared cm. FORMULA- 3cm+4cm=7cm 7x7= 49

-Rheanna A. 8-17

What I did was I square routed the given area from the red box which gave me 3cm for the perimeter, which makes the side length of the triangle 3cm, after i took the given 4cm from the blue box and added the 3cm from the red box + 4cm from the blue box together which equaled 7cm and thats the hypotenuse. Afterwards i multiplied the side lengths of the "C/big box" together and gave me the area of 49 squared cm.

-Rheanna A. 8-17

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