This is a classroom blog hub for Grade 8 students at Sargent Park School.
Thursday, March 01, 2012
Problem of the Week
Here is a new feature at the Mathzone. Leave your answers behind in the comments.
If you were given a can of cola that was 97% caffeine-free, how many cans of cola would you have to drink in order to consume the same amount of caffeine found in a regular cola?
cc photo http://www.flickr.com/photos/jonycunha/6806070265/
There is 38mg. caffeine inone can of coke. If I was given a 97% caffeine-free coke. Then there is 3% caffeine left. So 3%= 0.03 0.03x38=1.14mg 1.14mg of caffeine in one can.
mg 1.14 38 --- ------ = ------- can 1 n _ 38/1.14= 33.3 _ _ 1x33.3= 33.3 _ n=33.3 Then I rounded it down so I got 33 cans. I need 33 can of coke to consume same amount of regular coke.
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5 comments:
If there is 3% caffeine found in the cola, it would take 100 divided by 3 to equal the same amount.
There is 38mg. caffeine inone can of coke. If I was given a 97% caffeine-free coke. Then there is 3% caffeine left.
So 3%= 0.03
0.03x38=1.14mg
1.14mg of caffeine in one can.
mg 1.14 38
--- ------ = -------
can 1 n
_
38/1.14= 33.3
_ _
1x33.3= 33.3
_
n=33.3
Then I rounded it down so I got 33 cans.
I need 33 can of coke to consume same amount of regular coke.
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It’s a great post, you really are a good writer! I’m so glad someone like you have the time, efforts and dedication writing, for this kind of article… Helpful, And Useful.
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this coke picture is looking soo beautiful, can you tell me who captured it. thanks this time to get this opportunity Scholarship universities for mbbs in china for more details.
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