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30 comments:
So the question is asking "How come you gave me a 'C'" (a mark between 60%-69%)?
(The student evidently missed 3 questions out of the 14 questions on the test.)
Here's one of my theories:
Even though there are 14 questions that doesn't mean that each question is worth 1 mark.(If it were it would be 11 out of 14, since they missed the 3 questions. The percentage would be 78% which makes it a "B", but it is suppose to be a C)
A possible scenario could be that 11 questions in the test could have been 2 marks each, making a total of 22 marks.
And the other 3 questions then would be worth 4 marks each which in total would be 12 marks.
Therefore the whole test is hypothetically out of 34.
To finish off the deduction we go back to the fact that the student missed the 3 questions. We could assume that those 3 marks were the 3 that were worth 4 marks; therefore he/she must have received a total of "22 out of 34”. As a result the percentage would be 64% which is a "C".
(Please correct me if I got anything wrong. It would be really helpful.)
So the question is asking that why is he having C if I only missed 3 question out of 14.
A-80%-100%
B-70%-79%
C-60%-69%
D-50%-59%
F-0%-59%
So:
3-14=11
11/14=0.78
0.78x100=78%
that's wrong you don't know how much each question is worth.
So I estimated the the three questions are worth 5 points all together.
5-14=9
9/14=0.64
0.64x100=64%
So that is why I estimated 5 marks 9/14 which equals 64% a C.
So the question we have to answer is How come your giving me a "C"?
To answer this we need to know what a "C" is worth in a percent. Well a "C" is worth 60%-69%.
The test is maybe out of 14 but that doesn't mean each question will be divided up equally.
Let's say:
3 questions= worth 1 mark each
4 questions= worth 2 marks each
1 question= worth 3 marks each
The only way you would get a "C" on a test worth of 14 is if you get 9/14.
8/14= 57%
9/14= 64%
10/14=71%
A student must have got 5 marks removed if he missed 3 questions. (14-9=5)
There's many possible outcomes to create the number 5 with the numbers 1,2 and 3.
We will use:
A question worth 1, and 2 questions worth 2. (2+2+1=5)
So this shows how a student missed 3 questions and get a "C" on a test out of 14. (You would have to get 9 out of 14.)
The question states that the student got a "C" but only missed 3 question out of 14
A-80%-100%
B-70%-79%
C-60%-69%
D-50%-59%
F-0%-59%
3-14=11
then change it into a percent which is 11/14=.78 then multiply it by a hundred which is 78% it looks wrong because 78 percent is a "B" but the teacher gave him a "C" .
Lets just say there is 14 question but the Quiz is out of 28 and one of the Question that he missed is
Question1=1
Question2=1
Question3=3
so that equals to 5 so 5-14=9 then divide it by 14 you will get 0.64then multiply it by 100 you will get 64% which it equals to a "C"
and the only way to get a C is 9/14 because lets say you got 8 out of 14 it is 58% but if you got 10 out of 14 it is 71 percent so technically the only way to get a "C" is 9 out of 14
For example there is 7 question in the quiz
1)= 3 marks
2)= 2 marks
3)= 2 marks
4)= 2 marks
5)= 1 mark
6)= 1 mark
7)= 3 marks
and lets say he missed questions 5,6,7 witch equals to 5 and subtract it how much is the quiz
is out of which is 9 the find the percentage of it = 64%
PAULO EMETERIIO -873
The question states that some students only missed 3 questions out of 14 on a quiz and was given a C.
A-80%-100%
B-70%-79%
C-60%-69%
D-50%-59%
F-0%-59%
First off let's assume each question is worth 1 mark. They missed 3 question given a total of 11/14 which is 78%, therefore they should be given a B.
However, there are many possible reasons they were given a C. Let's say the first 12 questions on the quiz are worth 2 marks, giving a total of 24 marks, and the last 2 questions are worth 5 marks, making the whole quiz out of 34. Assuming they missed the last 3 questions;
question#12: 2marks
question#13: 5marks
question#14: 5marks
with the total of 12 marks taken away.
34-12=22
Given a total of 22/34 with a percentage of 64% which is a C.
The question directs that some students only missed 3 questions which were out of 14 on a quiz. The kids revived a C, so how was this possible?
American Grading System:
A-80%-100%
B-70%-79%
C-60%-69% <----------
D-50%-59%
F-0%-59%
*We know that to get a C, you must receive a grade of numbers between 60% and 69%.
If the students only missed 3 questions, it would become 11/14 if the marks per question were all equal. EX: All the questions out of 1.
11/14 = 0.78%
(11 ÷ 4)
0.78% = B
If she didn't acquire a B with the amount of even marks, this means that some of the questions weren't all marked by 1, and that some of the questions weren't always divided up equally.
Nevertheless, there are many other further possibilities that we can achieve to actually get that C. One probability is that the first 12 questions on the quiz are worth 2 marks. Because 2 x 12 = 24, we would have 24 marks. Remember that the questions from 1 to 11 were out of 2, counting the twelfth question which is out of 2 also. But what about the other marks? This leaves us with two more questions we have to deal with. The two questions could each have a mark out of 5, making those two questions marked out of 10. With the 24 marks associated with the 10 marks, this equals 34.
This would be a possible outcome they have encountered assuming that they missed the last 3 questions:
Question #12 - 2marks
Question #13 - 5marks
Question #14 - 5marks
+ ---------
12 marks
*Last 3 questions would evolve into 12 marks.
34-12=22
(22/34)
22 ÷ 34 = 0.64% <----- Grade of C.
So the question is "How come you gave me a C?", when the student only missed 3 questions out of 14.
A-80%-100%
B-70%-79%
C-60%-69%
D-50%-59%
F-0%-49%
Let's just say that each question is worth 1 mark, and the student missed 3 questions out of 14.
14-3=11
11/14=0.78
0.78x100=78%
So the student should have gotten a B.
But there are possible reasons why the student got a C.
Maybe the 11 questions are worth 2 marks, so the student has a total of 22 marks. The 3 questions could be worth 4 marks, so the student lost 12 marks. So the test is out of 34.
34-12=22 marks
22/34=0.64
0.64x100=64%
If the student received 22/34 on the test, then the percentage will be 64%, which is a C.
The big question of this word problem is that why did a student got a "C" when he/she only missed 3 question out of 14. So first we have to figure out what a "C" is.
A-80%-100%
B-70%-79%
C-60%-69%
D-50%-59%
F-0%-59%
Now we know that a "C" is 60%-69%, we need to figure out what percentage he/she got on the test. We always assume that the questions have the equal amount of percents, so he/she got 11/14, which is equal to 78.57%. 78.57% is a B not a C which did not make sence, so now we have to think why did he/she got a C. I have two theories.
The first one is the that same as the other people who left comments, the questions were worth differently, so the 3 questions he/she missed made a very big percentage of the mark. This theory is hard to be proved because of the lack of information about the test. We did not know how many question have different marks and how much difference it was. All the comments before me has done a great job of putting a number in the question, and giving a way to find out the answer, so I am not going to focus on explaining this theory because there is hundreds of different possiblities.
The second theory is that he/she might have got other questions wrong on the test, the question just said the he/she "missed" 3 question, but it didn't say if he/she got the other questions right or wrong. That can also be one possiblity. If the questions were still assumed to have the same worth of percentages, he/she has to have 2 question wrong plus the 3 question he/she missed in the test to get a C in his/her test result which will be 9/14 or 64.29%. If the questions have different values in percentage, we will have to put a number in the question.
Say questions 1-11 is all worth 1 mark, and questions 12-14 are worth two marks, the test will be out of 17. He/she missed question 1, 2, 3, and got question 14 and 12 wrong, he/she will have a mark of 64.71%. There will be a lot more of different possiblities, this is just one of them.
(Watermarks have been inserted, so be careful if you are trying to copy and paste!)
The question states that the student got a "C" but only missed 3 question out of 14
A-80%-100%
B-70%-79%
C-60%-69%
D-50%-59%
F-0%-59%
So its out of 14 and they missed 3 which makes 11/14 which equals 78% but there are a lot of reason that you could have got it wrong because assume that one of the questions were worth more then 1 maybe it was worth 5 and another one was wort 3 and another 4 which equals to a total of 12. so now if they have missed 3 question which the marks were 2, 2,1 which adds to a number of 8 that would mean they lost 5 marks out of 100% so now instead of getting a test out of 14-5 will equal to 9 and 9/14=0.64=64% so now 64% is between 60% and 69% which also equal to a C
The question is how come you gave me a C when i only missed 3 questions out of 14.
A - 80%-100%
B - 70%-79%
C - 60%-69%
D - 50%-59%
F - 0%-59%
Since they missed 3 questions out of 14 there mark should have been 78% but maybe not all questions are out of 1 mark
Question 1 -3 marks
Question 2 -2 marks
Question 3 -2 marks
Question 4 -1 mark
Question 5 -2 marks
Question 6 -2 marks
Question 7 -1 mark
Question 8 -1 mark
So the kids had test of 8 question worth 14 marks. So say they got 1,4 and 7 wrong they would have got 9 out of 14 which is 64% and that equals a C.:)
This question is asking " How come you are giving me a C when I only missed 3 question out of 14"?
D= 50%-59%
C= 60%-69%
B= 70%-80%
A= 80%-100%
I was thinking maybe the teacher made the 3 questions that her/he missed worth more than 1 mark. So 14-3=11. 11 of the 14 questions are equal to 9. 9 percent of 11 is = 64% which is a C. That's why they got a C. The other 3 marks are worth 5 marks so that's why they got a C.
Another way is that if you don't answer a question you automatically lose 1.5 marks. So you lose 4.5. 9.5% of 14% is 68% Which is a C.
Kyanna 8-73
The question states that the student got a "C" but only missed 3 question out of 14.
A-80%-100%
B-70%-79%
C-60%-69%
D-50%-59%
F-0%-59%
One possible explanation could be that the student also got other questions wrong along with the 3 they missed/skipped. If each question was worth 1 mark, then the 3 questions they missed would bring them down to a 78%. Along with that, the student may have gotten a few other questions wrong, which would bring their mark down to a "C".
Ex. A student skipped 3 out of 14 questions. Along with the 3 they skipped, they got another 2 questions wrong. That would give them a mark of 64% (9/14), which is a "C".
Mary Duong 8-16
The question was how come I got a C on a quiz where i only missed 3 questions out of 14.
First of all we know that a(n)
A=80-100%
B=70-79%
C=60-69%
D=50-59%
So to get a C you have to receive a mark of 60-69% But if every question was worth 1 mark you would get 78% which is a B. In this case he received a c probably because the questions may have been worth more than 1 mark.
For example:
Since there are 14 questions, there are many possibilities you can create to prove this.
Here is mine.
Questions 1-10 = 3 marks each.
Questions 11-14 = 6 marks each.
This would be out of 54 because
3x10=30 and 6x4=24. 30+24= 54
Since it says he missed 3. He may have missed 12, 13, and 14. These 3 questions are worth 18 marks together. So 54-18=36 so this is 36 out of 54. To find the percentage you just divide the numerator by the denominator and I got 66.66% or just 66% and that is worth a C mark.
Question: "How come you gave me a "C"?
- C is a mark between 60%-69%
- The student missed 3 out of 14 questions.
- If every question is worth 1 mark the percentage would be 78% (11/14=78%) which is not a C.
- This tells us that not all questions are 1 mark.
- My theory: (There are many ways to prove this!)
- Let's say that the total of all 14 questions is 74 and the student missed out 3 questions that might have worth a total of 25 marks. So there are 11 questions left which is worth 49 marks. Let's do the calculation (74(14)-49(11)=25(3).
-To get the percentage let's divide 74(14) by 49(11), it would equal to 66% which is a C.
The question is "How come the student got a "C" but he only missed 3 questions out of 14 questions all together."
Since the student only missed 3 questions out of 14 which is 11 out of 14, he would've gotten a percentage of 78% (11/14)and a "B".
A-80%-100%
B-70%-79%
C-60%-69%
D-50%-59%
F-0%-59%
Now just because the test was out of 14 dosen't mean that each question was worth 1 mark. A possible way that the student got a "C" is that 10 questions were 2 marks each, giving a total of 20 marks. (2*20)
And the other 4 questions were worth 5 marks each, giving a total of 20 marks. (4*5). So the whole test would be out of around 40.
(20+20).
So lets just say that the 3 questions that the student missed was worth 5 marks, therefore the student got a total of 25 out of
40. (40-15). So the percentage would've been 62.5% which would've gave the student the "C" that he/she deserves. (25/40=0.625)
(0.625*100=62.5%).
So the question is asking "How come you gave me a 'C'"
(The student evidently missed 3 questions out of the 14 questions on the test.)
So I think that
A-90%-100%
B-70%-80%
C-60%-70%
So now you have to find the percent of what the student got on their test to do that:
11/14= 0.78
then you have to multiply that by 100 so 0.78 times 100= 78%
well that doesn't work because a C is worth between 60% to 70%
So I think that the three marks he missed was 4.5 marks so you go
4.5-14=9.5
9.5/14=0.67
0.67 times 100= 67%
so that fits in 60 to 70 %
So the question is asking "How come you gave me a C if i only missed 3 questions out of 14
A-90%-100%
B-70%-80%
C-60%-70%
D-50%-60%
F below 50%
After you broke it down into parts you figure out the decimal they got
11/14= 0.78
then you have to multiply that by 100 so 0.78 times 100= 78%
But 78% would mean that the person got a B not a C .
BUT in the question in never said that all question were out of 1 so some questions could have been worth 2 or higher making the percent
so I'm thinking that aleast 3-4 questions are aleast 5 marks each so to solve it you go
5 -14= 9
9/ 14=0.64
0.64 multiplied by 100 =64%
That is whhy i thought some questions have to be more then 1 mark each.
Gurpreet 8-17
daphne amelo 8-73
So the question is "How come you gave me a "c" when I only missed 3 questions out of 14?"
A-80%-100%
B-70%-79%
C-60%-69%
D-50%-59%
F-0%-59%
*If each question is worth one mark, the percentage of 11 out of 14 would be 78% (100÷14=7.14..so 7.14x11=78.54, that's why it's 78%)
which is suppose to be a B, instead of a C. The only way you could get a C on a test is if you get a 9 out of 14, but in this case, the student had an 11 out of 14, which is suppose to be a B.
*But there are other possible reasons of why this person received a C (11 out of 14). He/ She could have got some other questions wrong besides the 3 question that she "MISSED". There is a possibility that she/ he got 2 other questions wrong PLUS the 3 that she "missed" which leads to a total of 9 out of 14, (or a 64%) which is a C.
*Another possible reason is that the test out of 14 doesn't mean that each question is worth one mark. The marks could be divided, for example:
4 questions= one mark each (4)
2 questions= two marks each (4)
3 questions= two marks each (6)
(^out of 14)
Lets say she missed the (2 questions which is 2 marks each, means that she already missed 2 questions worth 4 marks) and lets also say that she also missed one question from the 4 questions worth 1 mark. So, now.. she missed 2 questions worth 4 marks.. and she also missed one question worth one mark.. She missed three questions worth five marks.. so he/she got a 9/14 (64%)
-DAPHNE AMELO 873
So the question is "I only missed 3 questions out of 14...How come you gave me a 'C'?"
A-80%-100%
B-70%-79%
(C-60%-69%)
D-50%-59%
F-0%-59%
It says that the test is out of 14 a kid missed 3 marks so it would have given him/her 11 out of 14 (78%).
It also says that the test is out of 14, but it doesn't mean that the test has to have 14 questions, for instants:
Question 1: 3 marks
Question 2: 2 marks
Question 3: 3 marks
Question 4: 1 mark
Question 5: 2 marks
Question 6: 1 mark
Question 7: 2 marks
So lets say that the kid got number 2, 4 and 7 wrong, which would give them 9 out of 14 on the test, which is 64% so thats one way the kid could of gotten a c on this test.
Nicole P. 8-73
The question that they are asking us is "I only missed 3 questions out of 14, how come your giving me a 'c' ".
Okay, first we know:
A=80-100%
B=70-79%
C=60-69%
D=50-59%
To get a C you need to get a mark between 60-69%. But if each question was divided equally you would get a B which is 70-79%. So the only way to get a C is if some of the questions are more than 1 mark.
So, since the test was out of 14 that means there was 14 questions. You can solve this problem in many ways. For example:
Maybe the student missed questions 11-14, and they were 5 marks each.
So you go 5-14= 9
Then go 9÷14= 0.64
To get the percent you times it by 100. So the percent would be:
0.64x100= 64%
64% = C
because it is between 60-69%.
If i made a mistake please let me now, thank you.
The question states that the student got a "C" but only missed 3 question out of 14.
A-80%-100%
B-70%-79%
C-60%-69%
D-50%-59%
F-0%-59%
There are many theories of solving this question. Here's one of my theories. First, let's consider that each question is worth 1 mark, and they missed 3 questions. That's a total of 11/14 which is 78.57% (11÷14=0.7857, 0.7857x100=78.57%). So for this reason they should be given a B.
However, there are many possible reasons they were given a C. Let's say the first 12 questions on the quiz are worth 2 marks. Giving the quiz a total of 24 marks, and the last 2 questions were worth 5 marks. Making the entire quiz out of 34. Considering that they missed the last 3 questions;
question#12: 2marks
question#13: 5marks
question#14: 5marks
So overall they got 12 marks taken away. (34-12=22)
Given a total of 22/34. With a percentage of 64.70%(22÷34=0.6470, 0.6470x100=64.70%) which is a C.
Question: I only missed 3 questions out of 14... How come you're giving me "C"?
3 errors/ missed questions
14 questions
C= 60- 70%
Errors percentage is between 40- 30%
3x/14 = 0.3
3x = 14 x 0.3
3x=4.2
x = 4.2 ÷ 3= 1.4 but I rounded it and turn it into 1.5 because there's usually no such thing as 1.4 points (in marking).
x= 1.5
3x= 3(1.5)
3 x 1.5= 4.5 error points
14-4.5= 9.5 correct/ answered points
9.5 ÷ 14= 0.678 x 100= 67.8% or 68% w/c falls under "C" mark
Diana Basa 8-17
relThe question is "I only missed 3 questions out of 14, how come I got a C?"
So I know that the grading system is:
A: 80%-100%
B: 70%-79%
C: 60%-69%
D: 50%-59%
First of all lets think that each question is worth 1 mark and they missed 3 questions, those questions may be 11-14 and they could be 5 marks each.
Then you go 14-5=9
Then 9 divided by 14 is 0.64
To make 0.64 a percentage you have to multiply it by 100, so 0.64x100=64%
64% is a C because it is between 60 and 69!
Paige Blanca 8-17
Question: I only missed 3 questions out of 14... How come you're giving me a C?
A- 80-90%
B- 70-79%
C- 60-69% <------
There are many possibilities why this student got a C.
A possible answer why this student got a C is maybe because the worth of each question. 1 question can be worth 2 marks and another question can be worth 1 mark. Example: Test out of 14. 3-14 questions is 1 mark. First 2 questions are worth 2 marks. The student missed 3 questions worth 1 mark, 14-3=11, 11/14 change to decimal 0.78. Multiply 0.78 by 100, which makes it 78%. According to the question.. it doesn't say that much information about the test so he could have got other questions wrong. He probably got question number 1 wrong that's worth 2 marks. 11-2= 9, 9/14 in percent 0.64, 0.64x100= 64%
C = 60-69%, 64% is in between 60 and 69%. That is a possible way how the student got a C on the test.
The question is I only missed 3 questions out of 14 .. How come you're giving me a C?
A-80%-100%
B-70%-79%
C-60%-69%
D-50%-59%
F-0%-59%
So a C would be between 60%-69%
So 14 - 3 is 11 so they got 11
11 divided by 14= is about 78%-79%
So this means that the teacher gave the wrong mark.
But there is a reason why the teacher gave them a C because some questions could of have more than 1 question for example
question 1-10 were each 1 mark
question 11-14 were all worth2 marks each and it would be out of 16 and the percent would be 68% michael s 8-17
The reason the children might have gotten a c (60%-69%) because the questions could have been worth more the 1 mark. For example the 2 of the 3 questions they got wrong on could have been worth 2 marks. So, they would have 9 out of 14 marks ( 3 question wrong) which is c (64%).
Serena 8-14
The question is why are the students having a C if they only missed 3 of 14 questions. (C= 60%- 69%)
A reason for this maybe because of the 3 questions they missed they were worth 1.5 marks instead of 1 mark. That would mean that they missed 4.5 marks out of 14 marks. They would have gotten 9.5 out of 14. A total of a 68% = C.
The question is: I only missed 3 questions, but why are you giving me a “C”?
First of all, we all know that:
- The test is out of 14 questions
- The student missed 3 questions.
- The equivalent of…
A is 80%-100%
B is 70%-79%
C is 60%-69%
D is 50%-59%
F is 0%-59%
If every question worth 1 mark it means that the student got 11 out of 14. Now, we have to find out whether it’s a “C” or not, by finding the percent of 11/14.
14 ÷ 11= 0.78
0.78 x 100= 78%
If the question worth 1 mark, it would not be “C”, now we know that each question is not worth 1 mark. Let’s say that the first 12 questions worth 2 marks each and the last two question worth 5 marks (total of 34). The student missed question #1 (2 marks) question #13 (5 marks) and question #14 (5 marks). He/ she missed 12 marks out of 34. (He/she got 22 marks correct out of 34)
22 ÷ 34 = 0.65
0.65 x 100= 65
So, the student got the percentage of 65% on the quiz, which is a “C”.
The question was how come I got a C on a quiz where i only missed 3 questions out of 14.
First of all we know that a(n)
A=80-100%
B=70-79%
C=60-69%
D=50-59%
So to get a C you have to receive a mark of 60-69% But if every question was worth 1 mark you would get 78% which is a B. In this case he received a c probably because the questions may have been worth more than 1 mark.
For example:
Since there are 14 questions, there are many possibilities you can create to prove this.
Here is mine.
Questions 1-10 = 3 marks each.
Questions 11-14 = 6 marks each.
This would be out of 54 because
3x10=30 and 6x4=24. 30+24= 54
Since it says he missed 3. He may have missed 12, 13, and 14. These 3 questions are worth 18 marks together. So 54-18=36 so this is 36 out of 54. To find the percentage you just divide the numerator by the denominator and I got 66.66% or just 66% and that is worth a C mark.
The question is "I only missed 3question out of 14. How come you're giving me a C.
A=80%-100%
B=70%-79%
C=60%-69%
D=50%-59%
F=0%-49%
Each question is worth one mark and they missed 3. That's 11/14 which is 78.57% (11/14=0.7857 0.7857x100=78.57%). They shou;d be given a B.
However, if the first 12 questions is worth one mark and thelast two questions are worth three marks. It's going to be out of 18.
question 12:1 mark
question 13:3 marks
question 14:3 marks
TOTAL: 7 marks
18-7=11
11/18=0.6111
0.6111x100=61.11%
Which is between the C category.
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